randRange(2, 9) random() < 0.2
randRangeExclude(-20, 20, [-1, 0, 1]) getGCD(A, B)
IS_IRREDUCIBLE ? plus(A + "x", B) : GCD + "(" + plus(A / GCD + "x", B / GCD) + ")" toSentenceTex(getFactors(abs(A)).concat(["x"])) toSentenceTex(getFactors(abs(B)))

Factor the expression below completely. All coefficients should be integers.

`expr(["+", ["*", A, "x"], B])`

SOLUTION

To factor a binomial, you should first find the greatest common factor of all the terms.

The factors of `Ax` are Ax_FACTORS.
The factors of `B` are B_FACTORS.

The greatest common factor of `Ax` and `B` is `GCD`.

Since the greatest common factor is `1`, the expression is already in its most factored form.

Therefore the answer is the original expression, `SOLUTION`.

So we can factor out the `GCD`.

If we divide each of the terms in the original expression by `GCD` we get `\dfrac{Ax}{GCD} = plus((A/GCD) + "x")` and `\dfrac{B}{GCD} = B/GCD`.

So the factored expression is `SOLUTION`.